Optimal. Leaf size=171 \[ \frac {9 a^2 c^5 \tanh ^{-1}(\sin (e+f x))}{16 f}-\frac {3 a^2 c^5 \sec (e+f x) \tan (e+f x)}{16 f}-\frac {3 a^2 c^5 \sec ^3(e+f x) \tan (e+f x)}{8 f}+\frac {a^2 c^5 \sec (e+f x) \tan ^3(e+f x)}{4 f}+\frac {a^2 c^5 \sec ^3(e+f x) \tan ^3(e+f x)}{2 f}-\frac {4 a^2 c^5 \tan ^5(e+f x)}{5 f}-\frac {a^2 c^5 \tan ^7(e+f x)}{7 f} \]
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Rubi [A]
time = 0.21, antiderivative size = 171, normalized size of antiderivative = 1.00, number of steps
used = 14, number of rules used = 7, integrand size = 32, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.219, Rules used = {4043, 2691,
3855, 2687, 30, 3853, 14} \begin {gather*} -\frac {a^2 c^5 \tan ^7(e+f x)}{7 f}-\frac {4 a^2 c^5 \tan ^5(e+f x)}{5 f}+\frac {9 a^2 c^5 \tanh ^{-1}(\sin (e+f x))}{16 f}+\frac {a^2 c^5 \tan ^3(e+f x) \sec ^3(e+f x)}{2 f}-\frac {3 a^2 c^5 \tan (e+f x) \sec ^3(e+f x)}{8 f}+\frac {a^2 c^5 \tan ^3(e+f x) \sec (e+f x)}{4 f}-\frac {3 a^2 c^5 \tan (e+f x) \sec (e+f x)}{16 f} \end {gather*}
Antiderivative was successfully verified.
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Rule 14
Rule 30
Rule 2687
Rule 2691
Rule 3853
Rule 3855
Rule 4043
Rubi steps
\begin {align*} \int \sec (e+f x) (a+a \sec (e+f x))^2 (c-c \sec (e+f x))^5 \, dx &=\left (a^2 c^2\right ) \int \left (c^3 \sec (e+f x) \tan ^4(e+f x)-3 c^3 \sec ^2(e+f x) \tan ^4(e+f x)+3 c^3 \sec ^3(e+f x) \tan ^4(e+f x)-c^3 \sec ^4(e+f x) \tan ^4(e+f x)\right ) \, dx\\ &=\left (a^2 c^5\right ) \int \sec (e+f x) \tan ^4(e+f x) \, dx-\left (a^2 c^5\right ) \int \sec ^4(e+f x) \tan ^4(e+f x) \, dx-\left (3 a^2 c^5\right ) \int \sec ^2(e+f x) \tan ^4(e+f x) \, dx+\left (3 a^2 c^5\right ) \int \sec ^3(e+f x) \tan ^4(e+f x) \, dx\\ &=\frac {a^2 c^5 \sec (e+f x) \tan ^3(e+f x)}{4 f}+\frac {a^2 c^5 \sec ^3(e+f x) \tan ^3(e+f x)}{2 f}-\frac {1}{4} \left (3 a^2 c^5\right ) \int \sec (e+f x) \tan ^2(e+f x) \, dx-\frac {1}{2} \left (3 a^2 c^5\right ) \int \sec ^3(e+f x) \tan ^2(e+f x) \, dx-\frac {\left (a^2 c^5\right ) \text {Subst}\left (\int x^4 \left (1+x^2\right ) \, dx,x,\tan (e+f x)\right )}{f}-\frac {\left (3 a^2 c^5\right ) \text {Subst}\left (\int x^4 \, dx,x,\tan (e+f x)\right )}{f}\\ &=-\frac {3 a^2 c^5 \sec (e+f x) \tan (e+f x)}{8 f}-\frac {3 a^2 c^5 \sec ^3(e+f x) \tan (e+f x)}{8 f}+\frac {a^2 c^5 \sec (e+f x) \tan ^3(e+f x)}{4 f}+\frac {a^2 c^5 \sec ^3(e+f x) \tan ^3(e+f x)}{2 f}-\frac {3 a^2 c^5 \tan ^5(e+f x)}{5 f}+\frac {1}{8} \left (3 a^2 c^5\right ) \int \sec (e+f x) \, dx+\frac {1}{8} \left (3 a^2 c^5\right ) \int \sec ^3(e+f x) \, dx-\frac {\left (a^2 c^5\right ) \text {Subst}\left (\int \left (x^4+x^6\right ) \, dx,x,\tan (e+f x)\right )}{f}\\ &=\frac {3 a^2 c^5 \tanh ^{-1}(\sin (e+f x))}{8 f}-\frac {3 a^2 c^5 \sec (e+f x) \tan (e+f x)}{16 f}-\frac {3 a^2 c^5 \sec ^3(e+f x) \tan (e+f x)}{8 f}+\frac {a^2 c^5 \sec (e+f x) \tan ^3(e+f x)}{4 f}+\frac {a^2 c^5 \sec ^3(e+f x) \tan ^3(e+f x)}{2 f}-\frac {4 a^2 c^5 \tan ^5(e+f x)}{5 f}-\frac {a^2 c^5 \tan ^7(e+f x)}{7 f}+\frac {1}{16} \left (3 a^2 c^5\right ) \int \sec (e+f x) \, dx\\ &=\frac {9 a^2 c^5 \tanh ^{-1}(\sin (e+f x))}{16 f}-\frac {3 a^2 c^5 \sec (e+f x) \tan (e+f x)}{16 f}-\frac {3 a^2 c^5 \sec ^3(e+f x) \tan (e+f x)}{8 f}+\frac {a^2 c^5 \sec (e+f x) \tan ^3(e+f x)}{4 f}+\frac {a^2 c^5 \sec ^3(e+f x) \tan ^3(e+f x)}{2 f}-\frac {4 a^2 c^5 \tan ^5(e+f x)}{5 f}-\frac {a^2 c^5 \tan ^7(e+f x)}{7 f}\\ \end {align*}
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Mathematica [A]
time = 1.87, size = 102, normalized size = 0.60 \begin {gather*} \frac {a^2 c^5 \left (10080 \tanh ^{-1}(\sin (e+f x))-\sec ^7(e+f x) (2520 \sin (e+f x)-455 \sin (2 (e+f x))-616 \sin (3 (e+f x))+2380 \sin (4 (e+f x))-392 \sin (5 (e+f x))+245 \sin (6 (e+f x))+184 \sin (7 (e+f x)))\right )}{17920 f} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.35, size = 299, normalized size = 1.75
method | result | size |
risch | \(\frac {i c^{5} a^{2} \left (245 \,{\mathrm e}^{13 i \left (f x +e \right )}-1680 \,{\mathrm e}^{12 i \left (f x +e \right )}+2380 \,{\mathrm e}^{11 i \left (f x +e \right )}-4480 \,{\mathrm e}^{10 i \left (f x +e \right )}-455 \,{\mathrm e}^{9 i \left (f x +e \right )}-3920 \,{\mathrm e}^{8 i \left (f x +e \right )}-8960 \,{\mathrm e}^{6 i \left (f x +e \right )}+455 \,{\mathrm e}^{5 i \left (f x +e \right )}-3248 \,{\mathrm e}^{4 i \left (f x +e \right )}-2380 \,{\mathrm e}^{3 i \left (f x +e \right )}-896 \,{\mathrm e}^{2 i \left (f x +e \right )}-245 \,{\mathrm e}^{i \left (f x +e \right )}-368\right )}{280 f \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right )^{7}}+\frac {9 c^{5} a^{2} \ln \left ({\mathrm e}^{i \left (f x +e \right )}+i\right )}{16 f}-\frac {9 c^{5} a^{2} \ln \left ({\mathrm e}^{i \left (f x +e \right )}-i\right )}{16 f}\) | \(209\) |
norman | \(\frac {\frac {9 c^{5} a^{2} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{8 f}-\frac {15 c^{5} a^{2} \left (\tan ^{3}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2 f}+\frac {849 c^{5} a^{2} \left (\tan ^{5}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{40 f}-\frac {1152 c^{5} a^{2} \left (\tan ^{7}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{35 f}+\frac {1199 c^{5} a^{2} \left (\tan ^{9}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{40 f}+\frac {15 c^{5} a^{2} \left (\tan ^{11}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2 f}-\frac {9 c^{5} a^{2} \left (\tan ^{13}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{8 f}}{\left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )-1\right )^{7}}-\frac {9 c^{5} a^{2} \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )-1\right )}{16 f}+\frac {9 c^{5} a^{2} \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )}{16 f}\) | \(217\) |
derivativedivides | \(\frac {c^{5} a^{2} \left (-\frac {16}{35}-\frac {\left (\sec ^{6}\left (f x +e \right )\right )}{7}-\frac {6 \left (\sec ^{4}\left (f x +e \right )\right )}{35}-\frac {8 \left (\sec ^{2}\left (f x +e \right )\right )}{35}\right ) \tan \left (f x +e \right )+3 c^{5} a^{2} \left (-\left (-\frac {\left (\sec ^{5}\left (f x +e \right )\right )}{6}-\frac {5 \left (\sec ^{3}\left (f x +e \right )\right )}{24}-\frac {5 \sec \left (f x +e \right )}{16}\right ) \tan \left (f x +e \right )+\frac {5 \ln \left (\sec \left (f x +e \right )+\tan \left (f x +e \right )\right )}{16}\right )+c^{5} a^{2} \left (-\frac {8}{15}-\frac {\left (\sec ^{4}\left (f x +e \right )\right )}{5}-\frac {4 \left (\sec ^{2}\left (f x +e \right )\right )}{15}\right ) \tan \left (f x +e \right )-5 c^{5} a^{2} \left (-\left (-\frac {\left (\sec ^{3}\left (f x +e \right )\right )}{4}-\frac {3 \sec \left (f x +e \right )}{8}\right ) \tan \left (f x +e \right )+\frac {3 \ln \left (\sec \left (f x +e \right )+\tan \left (f x +e \right )\right )}{8}\right )-5 c^{5} a^{2} \left (-\frac {2}{3}-\frac {\left (\sec ^{2}\left (f x +e \right )\right )}{3}\right ) \tan \left (f x +e \right )+c^{5} a^{2} \left (\frac {\sec \left (f x +e \right ) \tan \left (f x +e \right )}{2}+\frac {\ln \left (\sec \left (f x +e \right )+\tan \left (f x +e \right )\right )}{2}\right )-3 c^{5} a^{2} \tan \left (f x +e \right )+c^{5} a^{2} \ln \left (\sec \left (f x +e \right )+\tan \left (f x +e \right )\right )}{f}\) | \(299\) |
default | \(\frac {c^{5} a^{2} \left (-\frac {16}{35}-\frac {\left (\sec ^{6}\left (f x +e \right )\right )}{7}-\frac {6 \left (\sec ^{4}\left (f x +e \right )\right )}{35}-\frac {8 \left (\sec ^{2}\left (f x +e \right )\right )}{35}\right ) \tan \left (f x +e \right )+3 c^{5} a^{2} \left (-\left (-\frac {\left (\sec ^{5}\left (f x +e \right )\right )}{6}-\frac {5 \left (\sec ^{3}\left (f x +e \right )\right )}{24}-\frac {5 \sec \left (f x +e \right )}{16}\right ) \tan \left (f x +e \right )+\frac {5 \ln \left (\sec \left (f x +e \right )+\tan \left (f x +e \right )\right )}{16}\right )+c^{5} a^{2} \left (-\frac {8}{15}-\frac {\left (\sec ^{4}\left (f x +e \right )\right )}{5}-\frac {4 \left (\sec ^{2}\left (f x +e \right )\right )}{15}\right ) \tan \left (f x +e \right )-5 c^{5} a^{2} \left (-\left (-\frac {\left (\sec ^{3}\left (f x +e \right )\right )}{4}-\frac {3 \sec \left (f x +e \right )}{8}\right ) \tan \left (f x +e \right )+\frac {3 \ln \left (\sec \left (f x +e \right )+\tan \left (f x +e \right )\right )}{8}\right )-5 c^{5} a^{2} \left (-\frac {2}{3}-\frac {\left (\sec ^{2}\left (f x +e \right )\right )}{3}\right ) \tan \left (f x +e \right )+c^{5} a^{2} \left (\frac {\sec \left (f x +e \right ) \tan \left (f x +e \right )}{2}+\frac {\ln \left (\sec \left (f x +e \right )+\tan \left (f x +e \right )\right )}{2}\right )-3 c^{5} a^{2} \tan \left (f x +e \right )+c^{5} a^{2} \ln \left (\sec \left (f x +e \right )+\tan \left (f x +e \right )\right )}{f}\) | \(299\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 398 vs.
\(2 (168) = 336\).
time = 0.28, size = 398, normalized size = 2.33 \begin {gather*} -\frac {96 \, {\left (5 \, \tan \left (f x + e\right )^{7} + 21 \, \tan \left (f x + e\right )^{5} + 35 \, \tan \left (f x + e\right )^{3} + 35 \, \tan \left (f x + e\right )\right )} a^{2} c^{5} + 224 \, {\left (3 \, \tan \left (f x + e\right )^{5} + 10 \, \tan \left (f x + e\right )^{3} + 15 \, \tan \left (f x + e\right )\right )} a^{2} c^{5} - 5600 \, {\left (\tan \left (f x + e\right )^{3} + 3 \, \tan \left (f x + e\right )\right )} a^{2} c^{5} + 105 \, a^{2} c^{5} {\left (\frac {2 \, {\left (15 \, \sin \left (f x + e\right )^{5} - 40 \, \sin \left (f x + e\right )^{3} + 33 \, \sin \left (f x + e\right )\right )}}{\sin \left (f x + e\right )^{6} - 3 \, \sin \left (f x + e\right )^{4} + 3 \, \sin \left (f x + e\right )^{2} - 1} - 15 \, \log \left (\sin \left (f x + e\right ) + 1\right ) + 15 \, \log \left (\sin \left (f x + e\right ) - 1\right )\right )} - 1050 \, a^{2} c^{5} {\left (\frac {2 \, {\left (3 \, \sin \left (f x + e\right )^{3} - 5 \, \sin \left (f x + e\right )\right )}}{\sin \left (f x + e\right )^{4} - 2 \, \sin \left (f x + e\right )^{2} + 1} - 3 \, \log \left (\sin \left (f x + e\right ) + 1\right ) + 3 \, \log \left (\sin \left (f x + e\right ) - 1\right )\right )} + 840 \, a^{2} c^{5} {\left (\frac {2 \, \sin \left (f x + e\right )}{\sin \left (f x + e\right )^{2} - 1} - \log \left (\sin \left (f x + e\right ) + 1\right ) + \log \left (\sin \left (f x + e\right ) - 1\right )\right )} - 3360 \, a^{2} c^{5} \log \left (\sec \left (f x + e\right ) + \tan \left (f x + e\right )\right ) + 10080 \, a^{2} c^{5} \tan \left (f x + e\right )}{3360 \, f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 2.55, size = 189, normalized size = 1.11 \begin {gather*} \frac {315 \, a^{2} c^{5} \cos \left (f x + e\right )^{7} \log \left (\sin \left (f x + e\right ) + 1\right ) - 315 \, a^{2} c^{5} \cos \left (f x + e\right )^{7} \log \left (-\sin \left (f x + e\right ) + 1\right ) - 2 \, {\left (368 \, a^{2} c^{5} \cos \left (f x + e\right )^{6} + 245 \, a^{2} c^{5} \cos \left (f x + e\right )^{5} - 656 \, a^{2} c^{5} \cos \left (f x + e\right )^{4} + 350 \, a^{2} c^{5} \cos \left (f x + e\right )^{3} + 208 \, a^{2} c^{5} \cos \left (f x + e\right )^{2} - 280 \, a^{2} c^{5} \cos \left (f x + e\right ) + 80 \, a^{2} c^{5}\right )} \sin \left (f x + e\right )}{1120 \, f \cos \left (f x + e\right )^{7}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} - a^{2} c^{5} \left (\int \left (- \sec {\left (e + f x \right )}\right )\, dx + \int 3 \sec ^{2}{\left (e + f x \right )}\, dx + \int \left (- \sec ^{3}{\left (e + f x \right )}\right )\, dx + \int \left (- 5 \sec ^{4}{\left (e + f x \right )}\right )\, dx + \int 5 \sec ^{5}{\left (e + f x \right )}\, dx + \int \sec ^{6}{\left (e + f x \right )}\, dx + \int \left (- 3 \sec ^{7}{\left (e + f x \right )}\right )\, dx + \int \sec ^{8}{\left (e + f x \right )}\, dx\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.82, size = 197, normalized size = 1.15 \begin {gather*} \frac {315 \, a^{2} c^{5} \log \left ({\left | \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 1 \right |}\right ) - 315 \, a^{2} c^{5} \log \left ({\left | \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - 1 \right |}\right ) - \frac {2 \, {\left (315 \, a^{2} c^{5} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{13} - 2100 \, a^{2} c^{5} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{11} - 8393 \, a^{2} c^{5} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{9} + 9216 \, a^{2} c^{5} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{7} - 5943 \, a^{2} c^{5} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{5} + 2100 \, a^{2} c^{5} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} - 315 \, a^{2} c^{5} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 1\right )}^{7}}}{560 \, f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 5.76, size = 251, normalized size = 1.47 \begin {gather*} \frac {-\frac {9\,a^2\,c^5\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^{13}}{8}+\frac {15\,a^2\,c^5\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^{11}}{2}+\frac {1199\,a^2\,c^5\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^9}{40}-\frac {1152\,a^2\,c^5\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^7}{35}+\frac {849\,a^2\,c^5\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^5}{40}-\frac {15\,a^2\,c^5\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3}{2}+\frac {9\,a^2\,c^5\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}{8}}{f\,\left ({\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^{14}-7\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^{12}+21\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^{10}-35\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^8+35\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^6-21\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4+7\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2-1\right )}+\frac {9\,a^2\,c^5\,\mathrm {atanh}\left (\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\right )}{8\,f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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